Lesson 11: The Other Formulas

There are several other formulas that are very useful when the acceleration is uniform.

Formula 1

A common problem is to figure out the final velocity of an object after it has been accelerating for a certain time.

This is not a "new" formula, but just a manipulation of the standard acceleration formula.

vf = vi + at

Example1: I’m driving my Camaro at 61km/h when I notice that there is a school zone ahead. If I slam on the brakes for 6.7s and experience acceleration of 1.5m/s2, determine if I will be under the 30km/h posted speed limit.

First, change the initial velocity into m/s…

vi = 61km/h = 16.9444444m/s

Remember to keep all these extra digits on your calculator, but keep track of the actual sig digs.

Keep in mind that since I was slowing down, the acceleration is negative.

Now use the formula. This one is so common, you don’t even need to show how you manipulated it if you remembered it.

vf = vi + at

= 17m/s + (-1.5m/s2)(6.7s)

= 6.894m/s = 24.81 km/h

vf = 25 km/h

Yep, I slowed down enough. Notice that I kept track of sig digs and changed it over to km/h at the end so I coould compare it to the posted speedlimit easily.

Formula 2

We will also do problems where we need to calculate the displacement of an accelerating object after a time interval has passed and we know its initial velocity.

d = vit + ½ at2

d = ½ at2

Example 2: Occasionally the US Air Force calls me in to test fly their “birds”. A few weeks back I was flying along in my F-22 at 97m/s when I decide to kick in the afterburners for 12.3s. If the afterburners can generate enough thrust to accelerate the F-22 at 26m/s2, determine how far I traveled during that time.

d = vit + ½ at2

= (97m/s)(12.3s) + ½ (26m/s2)(12.3s)2

d = 3.2e3 m

Example 3: I am in a F-22 that is on the runway. From rest, I accelerate the plane at 3.9m/s2 for 9.5s to reach take off velocity. Determine how long the runway have to be.

This is an example of a question where the initial velocity is zero (since I’m starting from rest), so…

d = vit + ½ at2

d = ½ at2

= ½ (3.9m/s2)(9.5s)2

= 1.8e2 m

Formula 3

There is a formula related to formula 2 that can be used when we know the final velocity instead of the initial.

d = vft - ½ at2

Formula 4

Another very useful formula is the following…

vf2 = vi2 + 2ad

Example 4: Determine the final velocity of a car that starts at 42 m/s and accelerates at 3.78m/s2 for a distance of 12 m.

vf2 = vi2 + 2ad

= (42m/s)2 + 2 (3.78m/s2) (12m)

vf2 = 1855
Many people leave the answer like this, forgetting that this is velocity squared!

vf = 43 m/s

Formula 5

The last formula I’ll show you is one of the least used ones.

d = ½ (vf+ vi) t

Example 5: Determine how far a vehicle moved if it started at 12 m/s and accelerated up to 47 m/s in a time of 34s.

d = ½ (vf+ vi) t

= ½ (47 m/s + 12 m/s) (34s)
Notice that it really doesn’t matter which order the velocities are added in.

d = 1.0e3 m

How to Choose the Right Formula!

So, how do you figure out which formula to use for a particular problem?

For example, if I had a question where I am given acceleration, displacement, and time, and asked to find initial velocity, I would choose the second formula.

Remember that for all of these formulas, you may be required to manipulate the formula to find the answer you are looking for.

Example 6: Determine the displacement of a car that starts at 10 m/s and accelerates at 1.89m/s2 and reaches a final speed of 32m/s.

vf2 = vi2 + 2ad
Can you see why I choose this formula?

d = (vf2 - vi2) / 2a

= (322-102) / 2(1.89)

d = 2.4e2 m