Lesson 42: Simple Harmonic Motion and Springs

A lot of things in nature repeat themselves over and over again as time passes.

This can be applied to very specific situations in physics called Simple Harmonic Motion (see Lesson 32).

A good example of SHM is the study of springs, and what they do when expanded or compressed.

A physicist named Robert Hooke studied this sort of a situation and came up with a few interesting observations.

Robert Hooke

He came up with the following formula based on these observations… it’s known as Hooke’s Law:

F = kx

F = force (N)
k = spring constant (N/m)
x = expansion or compression (m)

Example 1: If a spring has a spring constant of 18.5 N/m, determine the force needed to a) expand the spring 15cm and b) compress the spring 20cm from its equilibrium point.

a) F = kx = (18.5N/m) (+0.15m) = +2.8 N

b) F = kx = (18.5N/m) (-0.20m) = -3.7 N

Note: As always, a plus and negative sign only indicate direction. Expansion is thought of as being positive, while compression is traditionally seen as negative.

Now let’s relate Hooke's Law to SHM with some old physics.

It is also possible to calculate how energy is changing forms as the weight moves from its maximum distance to its equilibrium point.

Ee = elastic potential energy (J)
k = spring constant (N/m)
x = expansion or compression (m)

Example 2: A spring with a spring constant of 10 N/m is stretched to a distance of 32cm. We let go of the 5.0kg mass on the end of the spring. Determine how fast it will be moving when it a) is 12cm from the equilibrium point and b) at the equilibrium point.

a) At the start when it is 32cm from the equilibrium, it will have the following elastic potential energy

When it is 12cm from equilibrium we can figure out how much elastic potential energy it has …

This just means that some of the original elastic potential energy has turned into kinetic energy

Ek = 0.51 J – 0.072 J = 0.44 J

which we can use to find the speed of the weight…

b) At the equilibrium point, all of its original elastic potential energy has changed into kinetic energy

Ee = Ek = 0.51 J

which we can use to find the speed of the weight…